Equivalent Concept

The number of moles of $KMn{O}_4$ That will be needed to react with one mole of sulphite ion in acidic solution is

Vapour density of a metal chloride is 66. Its oxide contains 53% metal. The atomic weight of the metal is

$1.1 \mathrm{g} {\mathrm{CH}}_3{\left({\mathrm{CH}}_2\right)}_{\mathrm{n}}\mathrm{COOH}$ was burnt in excess of air and the resultant gases $\left({\mathrm{CO}}_2+{\mathrm{H}}_2\mathrm{O}\right)$ were passed through a solution of $\mathrm{NaOH}$. The resulting solution is divided into two equal parts. One part required $75$m.e. of $\mathrm{HCl}$ for neutralisation using phenolphthalein as indicator. The other part required $100$ m.e. of $\mathrm{HCl}$ using methyl orange as indicator. Find $\mathrm{n}$.

Find out the normality of a solution obtained by mixing $0.45 \mathrm{N} \mathrm{KOH}$ and $0.60 \mathrm{N}$ $\mathrm{NaOH}$ in the ratio $2:1$ by volume.

${\mathrm{KMnO}}_4$ reacts with ${\mathrm{H}}_2{\mathrm{O}}_2$ in an acidic medium. The number of moles of oxygen produced per mole of ${\mathrm{KMnO}}_4$ is;

20 mL solution of 0.1 M ferrous sulphate was completely oxidised using a suitable oxidising agent. What is the number of electrons exchanged?

What are the number of moles of KMnO₄ that will be needed to react with one mole of ${\mathrm{SO}}_3^{2-}$ion  in acidic solution?

How many equivalents of $\mathrm{Mg}$ would have to react in order to liberate $4{ \mathrm{N}}_{\mathrm{A}}$ electrons? $\left(\mathrm{Mg}-2{\mathrm{e}}^{-}\to {\mathrm{Mg}}^{2+}\right)$

Molten ${\mathrm{AlCl}}_3$ is electrolysed with a current of $0.5 \mathrm{A}$ to produce $27.0 \mathrm{g}$ $\mathrm{Al}$.

How many litres of ${\mathrm{Cl}}_2$ at NTP were produced?(Report the answer in 2 significant numbers)

Upon heating a litre of a $\frac{\mathrm{N}}{2}\mathrm{HCl}$ solution, $2.675 \mathrm{g}$ of hydrogen chloride is lost and the volume of the solution shrinks to $750 \mathrm{mL}$. Calculate:

The normality of the resultant solution.(Express your answer up to three decimal places)

Find the equivalent weight of ${\mathrm{H}}_3{\mathrm{PO}}_4$, in the reaction,

$\left[\mathrm{Ca}(\mathrm{OH}{)}_2+{\mathrm{H}}_3{\mathrm{PO}}_4={\mathrm{CaHPO}}_4+2{\mathrm{H}}_2\mathrm{O}\right]$.

If $2 \mathrm{litres}$ of ammonia at $13 °\mathrm{C}$ and $0.90$ atmospheric pressure is neutralised by $134 \mathrm{ml}$ of ${\mathrm{H}}_2{\mathrm{SO}}_4$ solution, the normality value of the acid is A.

Report the value of A by multiplying with 100 and rounding off the value to two significant figures

How many gram of ${\mathrm{H}}_2\mathrm{S}$ will react with $63.2 \mathrm{g}$ of ${\mathrm{KMnO}}_4$ to produce ${\mathrm{K}}_2{\mathrm{SO}}_4$ and ${\mathrm{MnO}}_2?$ Give answer after rounding off to the nearest integer.

A certain amount of metal, whose equivalent weight is $28,$ displaces $0.7 \mathrm{litre}$ of hydrogen measured at NTP from an acid. Calculate the weight of the metal.

Give your answer to the nearest integer value after multiplying with 4.

In the quantitative estimation of hypo$({\mathrm{Na}}_2 {\mathrm{S}}_2{\mathrm{O}}_3.5{\mathrm{H}}_2\mathrm{O})$ with potassium permanganate in faintly alkaline or neutral medium, the equivalent weight of hypo is ________(round off to the nearest integer)

If $6\times {10}^{-3} \mathrm{mole}$ of ${\mathrm{K}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7$ reacts completely with $9\times {10}^{-3}$ mole of ${\mathrm{X}}^{\mathrm{n}+}$ to give ${\mathrm{XO}}_3^{-} \text{and} {\mathrm{Cr}}^{3+}$, then, the value of $\mathrm{n}$ is